Vb Net Lab Programs For Bca Students Fix !!install!! Link
Dim choice As Integer = Convert.ToInt32(Console.ReadLine())
Dim student As New Student(studentID, name, email, phoneNumber, address) students.Add(student)
Imports System Module PrimeProgram Sub Main() Dim num As Integer Dim isPrime As Boolean = True Console.Write("Enter an integer to check: ") If Integer.TryParse(Console.ReadLine(), num) Then If num <= 1 Then isPrime = False Else ' Optimize loop by checking up to the square root For i As Integer = 2 To Convert.ToInt32(Math.Sqrt(num)) If num Mod i = 0 Then isPrime = False Exit For End If Next End If If isPrime Then Console.WriteLine($"num is a Prime Number.") Else Console.WriteLine($"num is not a Prime Number.") End If Else Console.WriteLine("Invalid input. Please enter a valid integer.") End If Console.ReadLine() End Sub End Module Use code with caution. 2. Object-Oriented Programming (OOP) Applications
' Use Double to handle decimal inputs; handle equality Dim a As Double = Val(txtNo1.Text) Dim b As Double = Val(txtNo2.Text) If a > b Then txtRes.Text = "A is Greater" ElseIf b > a Then txtRes.Text = "B is Greater" Else txtRes.Text = "Both are Equal" End If Use code with caution. Copied to clipboard Fix Detail instead of Integer.Parse() vb net lab programs for bca students fix
Dim frm As New Form frm.Controls.Add(dgv) frm.ShowDialog() Catch ex As Exception MessageBox.Show("Error: " & ex.Message) Finally conn.Close() End Try End Sub End Class
Public Class PrimeForm Private Sub btnCheck_Click(sender As Object, e As EventArgs) Handles btnCheck.Click Dim num As Integer If Integer.TryParse(txtInput.Text, num) AndAlso num > 1 Then Dim isPrime As Boolean = True For i As Integer = 2 To Math.Sqrt(num) If num Mod i = 0 Then isPrime = False Exit For End If Next If isPrime Then lblOutput.Text = num & " is a Prime Number." Else lblOutput.Text = num & " is a Composite Number." End If Else lblOutput.Text = "Please enter an integer greater than 1." End If End Sub End Class Use code with caution. Common Error & Fix
Crashing with an InvalidCastException or FormatException when a student leaves a TextBox blank or types text instead of numbers. Dim choice As Integer = Convert
Public Sub New() students = New List(Of Student) conn = New SqlConnection("Data Source=(local);Initial Catalog=StudentDB;Integrated Security=True") End Sub
Imports System.Data.SqlClient Public Class DatabaseForm ' Update the connection string according to your local instance configuration Dim connStr As String = "Data Source=(localdb)\MSSQLLocalDB;Initial Catalog=BcaLabDB;Integrated Security=True" Private Sub btnSave_Click(sender As Object, e As EventArgs) Handles btnSave.Click Dim query As String = "INSERT INTO Students (ID, SName) VALUES (@ID, @Name)" Using conn As New SqlConnection(connStr) Using cmd As New SqlCommand(query, conn) cmd.Parameters.AddWithValue("@ID", Convert.ToInt32(txtID.Text)) cmd.Parameters.AddWithValue("@Name", txtName.Text) Try conn.Open() cmd.ExecuteNonQuery() MessageBox.Show("Record inserted successfully!") LoadGridData() Catch ex As Exception MessageBox.Show("Database Error: " & ex.Message) End Try End Using End Using End Sub Private Sub LoadGridData() Dim query As String = "SELECT * FROM Students" Using conn As New SqlConnection(connStr) Dim da As New SqlDataAdapter(query, conn) Dim ds As New DataSet() da.Fill(ds, "Students") dgvRecords.DataSource = ds.Tables("Students") End Using End Sub End Class Use code with caution. Common Bugs & Fixes
Imports System.Data.SqlClient
result = 7/2 gives 3.5, but result = 7\2 gives 3. Fix: In VB.NET, / returns a Double. \ returns an Integer after rounding. For precise division in BCA lab reports, use CDec() or convert to double first.
Public Class Form1 Private Sub btnCheck_Click(sender As Object, e As EventArgs) Handles btnCheck.Click Dim inputStr As String = txtInput.Text Dim reverseStr As String = StrReverse(inputStr)